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Question
A heater draws a current of 5A at 220 V for 2 minutes. The energy released by heater in kilojoules is:
Options
132 kJ
66 kJ
99 kJ
33 kJ
MCQ
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Solution
132 kJ
Explanation:
t = 2 × 60 = 120 s
W = V × I × t
= 220 × 5 × 120
= 132000 J
= 132 kJ
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