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Question
A guy wire attached to a vertical pole of height 18 m is 24m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?
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Solution
Let AB be a guy wire attached to a pole BC of height 18 m. Now, to keep the wire taut let it to be fixed at A.
Now, In right triangle ABC
By using Pythagoras theorem, we have
`AB^2=BC^2+CA^2`
⇒ `24^2=18^2+CA^2`
`⇒ CA^2=576-324`
`⇒ CA^2=252`
`⇒ CA=6sqrt7` m
Hence, the stake should be driven` 6 sqrt7`𝑚 far from the base of the pole.
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