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Question
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A golf ball is spherical with about 300–500 dimples that help increase its velocity while in play. Golf balls are traditionally white but available in colours also. In the given figure, a golf ball has diameter 4.2 cm and the surface has 315 dimples (hemispherical) of radius 2 mm.
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Based on the above information, answer the following questions.
- Find the surface area of one such dimple.
- Find the volume of the material dug out to make one dimple.
- Find the total surface area exposed to the surroundings.
- Find the volume of the golf ball.
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Solution
i. Surface area of one dimple
Given: Radius of hemispherical dimple, \[r = 2\text{ mm} = 0.2\text{ cm}\]
Formula: \[\text{CSA} = 2\pi r^2\]
Calculation: \[\text{CSA} = 2 \times \frac{22}{7} \times 0.2 \times 0.2\]
\[\text{CSA} = \frac{1.76}{7} \approx 0.2514\text{ cm}^2\]
ii. Volume of material dug out to make one dimple
Formula: \[V = \frac{2}{3}\pi r^3\]
Calculation: \[V = \frac{2}{3} \times \frac{22}{7} \times (0.2)^3\]
\[V = \frac{2}{3} \times \frac{22}{7} \times 0.008 \approx 0.01676\text{ cm}^3\]
iii. Total surface area exposed to the surroundings
Given: Radius of ball, \[R = \frac{4.2}{2} = 2.1\text{ cm}\]
Formula: \[\text{Exposed Area} = \text{Surface Area of sphere} - 315 \times (\pi r^2) + 315 \times (2\pi r^2)\]
\[\text{Exposed Area} = 4\pi R^2 + 315\pi r^2 = \pi \left(4R^2 + 315r^2\right)\]
Calculation: \[\text{Exposed Area} = \frac{22}{7} \left[4(2.1)^2 + 315(0.2)^2\right]\]
\[\text{Exposed Area} = \frac{22}{7} [4(4.41) + 315(0.04)]\]
\[\text{Exposed Area} = \frac{22}{7} [17.64 + 12.60]\]
\[= \frac{22}{7} \times 30.24\]
\[= 95.04\text{ cm}^2\]
iv. Volume of the golf ball
Formula: \[\text{Volume} = \text{Volume of sphere} - 315 \times \text{Volume of one dimple}\]
Calculation: \[\text{Volume of sphere} = \frac{4}{3} \times \frac{22}{7} \times (2.1)^3 = 38.808\text{ cm}^3\]
\[\text{Volume of 315 dimples} = 315 \times \left(\frac{2}{3} \times \frac{22}{7} \times (0.2)^3\right) = 5.28\text{ cm}^3\]
\[\text{Volume of golf ball} = 38.808 - 5.28 = 33.528\text{ cm}^3\]

