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Question
A glass block is having refractive index 3/2, the light ray is incident at an angle 45°. Find the sine of the angle of, refraction inside the glass block.
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Solution
∵ According to Snell's law of refraction:
n = `sin"i"/sin"r"`
`3/2=(sin45°)/sin"r"`
⇒ `3/2=(1//sqrt2)/sin"r"`
sin r = `2/(3sqrt2)`
= `sqrt2/3`
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|
S. No. |
∠i |
∠i |
∠e |
|
I |
30° |
20° |
31° |
|
II |
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|
III |
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