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Question
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A frog jumps 2 steps at a time. |
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A squirrel jumps 3 steps. |
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A rabbit jumps 5 steps. |
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A horse jumps 15 steps. |
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A kangaroo jumps 30 steps. |
Will the rabbit ever be at the number 18?
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Solution
No, the rabbit will never be at the number 18.
The rabbit jumps 5 steps. 18 is not divisible by 5. So, the rabbit will never arrive at the number 18.
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![]() |
A frog jumps 2 steps at a time. |
![]() |
A squirrel jumps 3 steps. |
![]() |
A rabbit jumps 5 steps. |
![]() |
A horse jumps 15 steps. |
![]() |
A kangaroo jumps 30 steps. |
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27 ÷ 3 = ______
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A frog jumps 2 steps at a time. |
![]() |
A squirrel jumps 3 steps. |
![]() |
A rabbit jumps 5 steps. |
![]() |
A horse jumps 15 steps. |
![]() |
A kangaroo jumps 30 steps. |
Which is the smallest number where the frog and the squirrel will meet?
Try these.
| 4 ÷ ______ | = | 2 | ______ |
| 14 ÷ 7 | = | ______ | ______ |
| 6 ÷ 3 | = | ______ | ______ |
| ______ ÷ 2 | = | 7 | ______ |
| ______ ÷ 2 | = | 3 | ______ |
| 15 ÷ 3 | = | ______ | ______ |
| 8 ÷ 4 | = | ______ | ______ |
| 15 ÷ 5 | = | ______ | ______ |
| 8 ÷ ______ | = | 4 | ______ |
| ______ ÷ 2 | = | 8 | ______ |
Divide the clock face into three parts so that the sum of the numbers in each part is the same.















