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Question
A force defined by F = αt2 + βt acts on a particle at a given time t. The factor which is dimensionless, if α and β are constants, is ______.
Options
αβt
αβ/t
βt/α
αt/β
MCQ
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Solution
A force defined by F = αt2 + βt acts on a particle at a given time t. The factor which is dimensionless, if α and β are constants, is αt/β.
Explanation:
Given: F = αt2 + βt
The dimensions of force are:
F = [M L T−2]
From αt2:
αt2 = [M L T−2]
⇒ α = `([M L T^-2])/T^2
= M L T−4
From βt:
βt = M L T−2
⇒ β = `([M L T^-2])/T`
= M L T−3
`alpha/beta = ([M L T^-4])/([M L T^-3])`
= T−1
αt = M L T−4 . T = M L T−3
β = M L T−3
So,
`(alpha t)/beta` = 1
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