Advertisements
Advertisements
Question
A force acts for 0.1 s on a body of mass 3.2 kg initially at rest. The force then ceases to act and the body moves through 3 m in the next one second. Calculate the magnitude of force.
Advertisements
Solution
Time for which force is applied =0.1 s.
Mass of the body = 3.2 kg.
Initial speed of body = 0 ms-1
After removal of forces body covers a distance of 3m in 1 second so final speed of body = 3/1 = 3ms-1.
We know FX t = m (v - u)
F X 0.1 = 3.2 (3 -0)
F = 9.6/0.1 = 96 N.
So applied force is 96 N.
APPEARS IN
RELATED QUESTIONS
A body of mass 500 g, initially at rest, is acted upon by a force which causes it to move a distance of 4 m in 2 s, Calculate the force applied.
How does the gravitational force of attraction between two masses depend on the distance between them?
Define gravitational constant G.
Write the numerical value of gravitational constant G with its S.I. unit .
Name the physical quantity associated with the motion of a body.
What will be the momentum of a body at rest?
If a number of forces act on a stationary body at the same point, then what do you conclude from it?
Why do passengers tend to fall sideways when the bus takes a sharp turn?
Can internal forces change the velocity of a body?
Define the constant of gravitation.
