Advertisements
Advertisements
Question
A force acts for 0.1 s on a body of mass 3.2 kg initially at rest. The force then ceases to act and the body moves through 3 m in the next one second. Calculate the magnitude of force.
Advertisements
Solution
Time for which force is applied =0.1 s.
Mass of the body = 3.2 kg.
Initial speed of body = 0 ms-1
After removal of forces body covers a distance of 3m in 1 second so final speed of body = 3/1 = 3ms-1.
We know FX t = m (v - u)
F X 0.1 = 3.2 (3 -0)
F = 9.6/0.1 = 96 N.
So applied force is 96 N.
APPEARS IN
RELATED QUESTIONS
What is the C.G.S. unit of force? How is it defined?
A body of mass 500 g, initially at rest, is acted upon by a force which causes it to move a distance of 4 m in 2 s, Calculate the force applied.
Write an expression for the force due to gravity on a body of mass m and explain the meaning of symbols used in it.
Explain the following:
Why does a boatman push the bank backward with a long bamboo pole, on launching his boat in the water?
State unit of mass in CGS system.
Describe, briefly how can you calculate the value of ‘g’ with a simple pendulum.
What will be the momentum of a body at rest?
If a number of forces act on a stationary body at the same point, then what do you conclude from it?
Define acceleration due to gravity.
Define one newton. What is the ratio of SI to CGS units of force?
