Advertisements
Advertisements
Question
A cricket ball of mass 500 g moving at a speed of 30 ms 1 is brought to rest by a player in 0.03 s. Find the average force applied by the player.
Advertisements
Solution
Mass of ball = 500g = 0.5 kg.
Initial speed of the ball = 30 ms-1
Final speed of ball = 0 ms-1
Time taken by player to stop the ball = 0.03 s.
We know FX t = m (v - u)
F X 0.03 = 0.5 (0 - 30)
F = - 1.5 / 0.03 = - 500 N
(- ) sign shows that player has to apply force in opposite direction of the motion of the ball.
APPEARS IN
RELATED QUESTIONS
What do you understand by the term weight?
State two important characteristics of weight
Does a body weigh the same at all places of the Earth? Give a reason for your answer.
A man sits in a machine which generates acceleration five times more than the acceleration due to gravity. If the mass of the man is 80 kg, what is his weight? Take g = 10 ms−2.
A man weigh 800 N at the equator. How does the weight of man change at the following place?
At poles
How is weight affected in the following case, when initially the body is weighed in Delhi with a spring balance?
Body is taken to sea level.
Why do objects fall towards the earth?
Where do you weigh more: at the poles or at equator?
Two equal and opposite forces act on a moving body. How is its motion affected?
Where will a person weigh more: at Simla or at Delhi?
