Question

A field is `16 1/2` m long and `12 2/5` m wide. Find the perimeter of the field.

Answer 1

Length of field = `16 1/2` m

Breadth of field = `12 2/5` m

∴ Perimeter of field = 2 (l + b)

`= 2 xx (16 1/2 + 12 2/5)`

`= 2 xx (33/2 + 62/5)`

`= 2 xx ((33 xx 5)/(2 xx 5) + (62 xx 2)/(5 xx 2))`
(∵ L.C.M. of 2 and 5 = 10)

`= 2 xx ((165 + 124)/10)`

`= 2 xx 289/10 = 289/5 "m" = 57 4/5 "m"`