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A farmer prepares rectangular vegetable garden of area 180 sq meters. With 39 meters of barbed wire, he can fence the three sides of the garden, leaving one of the longer sides unfenced.

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Question

A farmer prepares rectangular vegetable garden of area 180 sq meters. With 39 meters of barbed wire, he can fence the three sides of the garden, leaving one of the longer sides unfenced. Find the dimensions of the garden. 

Sum
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Solution

Let the length and breadth of the rectangular garden be x and y meter, respectively.

Given:   

xy = 180 sq m   ...(i)  and 

2y + x = 39 

⇒ x = 39 – 2y 

Putting the value of x in (i), we get: 

(39 – 2y)y = 180 

⇒ 39 – 2y2 = 180 

⇒ 39y – 2y2 – 180 = 0 

⇒ 2y2 – 39y + 180 = 0

⇒ 2y2 – (24 + 15)y + 180 = 0 

⇒ 2y2 – 24y – 15y + 180 = 0 

⇒ 2y(y – 12) – 15(y – 12) = 0 

⇒ (y – 12)(2y – 15) = 0 

⇒ y = 12 or y = `15/2 = 7.5` 

If y = 12, x = 39 – 24 = 15 

If y = 7.5, x = 39 – 15 = 24 

Thus, the length and breadth of the garden are (15 m and 12 m) or (24 m and 7.5 m), respectively.

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Chapter 4: Quadratic Equations - EXERCISE 4D [Page 229]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 4 Quadratic Equations
EXERCISE 4D | Q 65. | Page 229
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