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Question
A Dihybrid cross is done between two parent pea plants (pure line) who differ in two pairs of contrasting traits: Seed colour and seed shape.
In the F2 generation the number of phenotypes and genotypes will be:
Options
phenotypes = 4; genotypes = 16
phenotypes = 9; genotypes = 14
phenotypes = 4; genotypes = 8
phenotypes = 4; genotypes = 9
MCQ
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Solution
phenotypes = 4; genotypes = 9
Explanation:
In the F2 generation, a dihybrid cross has a 1 : 2 : 1 : 2 : 4 : 1 : 2 : 2 : 1 genotypic ratio and a 9 : 3 : 3 : 1 phenotypic ratio, which means there are:
4 phenotypes (different physical traits)
9 genotypes (genetic combinations)
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