Question

A die is  thrown once. The probability of getting a prime number is 

Answer 1

`1/2`

Explanation:

  In a single throw of a die, the possible outcomes are:

    1, 2, 3, 4, 5, 6

 Total number of possible outcomes = 6

Let E be the event of getting a prime number.

Then, the favourable outcomes are 2, 3 and 5.

Number of favourable outcomes = 3

∴ Probability of getting a prime number =  P (E) = `("Number of favourable outcomes")/("Number of all possible outcomes")=3/6 = 1/2`