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Question
A die is thrown once. Find the probability of getting a number greater than or equal to 4.
Sum
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Solution
In throwing a dice, total possible outcomes = {1, 2, 3, 4, 5, 6}
n(S) = 6
On a dice, number greater than or equal to 4 = {4, 5, 6}
n(E) = 3
Probability of getting a number greater than or equal to 4
= `(n(E))/(n(S))`
= `3/6`
= `1/2`
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