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Question
A die is thrown, find the probability of getting:
a number not greater than 4.
Sum
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Solution
A die has six numbers: 1, 2, 3, 4, 5, 6
∴ Number of possible outcomes = 6
Number of favourable outcomes = not greater than 4 or numbers will be 1,2,3,4 which are 4 in numbers
P(E) = `"Number of favourable outcomes"/"Number of all possible outcomes"`
= `4/6 = 2/3`
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