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Question
A die has its six faces marked 0, 1, 1, 1, 6, 6. If two such dice are thrown together, then the probability of getting a total of 7 is ______.
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Solution
A die has its six faces marked 0, 1, 1, 1, 6, 6. If two such dice are thrown together, then the probability of getting a total of 7 is `underlinebb(1/3)`.
Explanation:
A total of 7 occurs with one die showing 1 and the other showing 6.
There are \[3\times2+2\times3=12\] such face-outcome pairs out of 36.
Thus, the probability is \[\frac{12}{36}=\frac{1}{3}\].
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