Question

A cylindrical bucket, whose base radius is 20 cm, is filled with water to a height of 25 cm. A heavy iron spherical ball of radius 10 cm is dropped to submerge completely in water in the bucket. Find the increase in the level of water. 

Answer 1

Radius of sphere = 10 cm 

Volume of sphere = `4/3pir^3`

 = `4/3 xx 22/7 xx 10 xx 10 xx 10  "cm"^3`

= 4190.476 cm³

Therefore , Volume of water = 4190.476 cm³

Radius of base of cylinder = 20 cm 

Let h be the height of the water

⇒ `pir^2h = 4190.476`

⇒ `22/7 xx 20 xx 20 xx h = 4190.476`

⇒ `1257.143 h = 4190.476`

⇒ h = 3.33 cm

lncrease in water level = 3.33 cm