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Karnataka Board PUCPUC Science Class 11

A Current of 5.0 a Exists in the Circuit Shown in the Figure. the Wire Pq Has a Length of 50 Cm and the Magnetic Field in Which It is Immersed Has a Magnitude

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Question

A current of 5.0 A exists in the circuit shown in the figure. The wire PQ has a length of 50 cm and the magnetic field in which it is immersed has a magnitude of 0.20 T. Find the magnetic force acting on the wire PQ.

Sum
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Solution

Given:
Length of the wire PQ inside the magnetic field, = 50 cm
Electric current through the wire, I = 5 A
Magnetic field, B = 0.2 T
The direction of magnetic field is perpendicular to the plane of the frame and it is going into the plane of the circuit.
As per the question,

Angle between the plane of the wire and the magnetic field, θ = 90˚
Magnetic force,
`vecF = vecil xx vecB`
`therefore |vecF| = ilBsintheta`
`therefore |vecF| = ilBsin906circ`
= 5 × 50 × 10−2 × 0.2 × 1
= 0.50 N
The direction of force can be found using Fleming's left-hand rule.
Thus, the direction of magnetic force is upwards in the plane of the paper.

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Chapter 34: Magnetic Field - Exercises [Page 231]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 34 Magnetic Field
Exercises | Q 11 | Page 231
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