English

A container, open at the top, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm, respectively.

Advertisements
Advertisements

Question

A container, open at the top, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm, respectively. Find the cost of milk which can completely fill the container at the rate of ₹ 21 per litre.

Sum
Advertisements

Solution

We have,

Height, h = 24 cm,

Upper radius, R = 20 cm ad 

Lower radius, R =  8 cm

Now,

A container, open at the top, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm, respectively. Find the cost of milk which can completely fill the container at the rate of ₹21 per litre.

Volume of the the container `= 1/3pi"h"("R"^2+r^2+Rr)`

`= 1/3 xx 22/7xx24xx(20^2 + 8^2 +20xx8)`

`= 176/7xx(400+64+160)`

`=176/7xx624`

`=109824/7 "cm"^3`

`= 109824/7  "L"`        (As, 1000 cm3 = 1 L)

So, the cost of the millk in the  container `= 109.824/7 xx 21`= 329.4712

≈ ₹ 329.47

shaalaa.com
  Is there an error in this question or solution?
Chapter 17: Volumes and Surface Areas of Solids - EXERCISE 17С [Page 823]

APPEARS IN

R.S. Aggarwal Mathematics [English] Class 10
Chapter 17 Volumes and Surface Areas of Solids
EXERCISE 17С | Q 4. | Page 823
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×