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A conductor of length 80 cm has a resistance of 4.80 Ω, calculate the resistance of similar conductor of length 640 cm.

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Question

A conductor of length 80 cm has a resistance of 4.80 Ω, calculate the resistance of similar conductor of length 640 cm.

Numerical
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Solution

Since the conductors are similar, they are made of the same material and have the same area of cross-section. Therefore, resistance is directly proportional to length.

R ∝ l

So, `R_1/R_2 = l_1/l_2`

Here, R1 = 4.80 Ω, l1 = 80 cm, l2 = 640 cm

`R_2 = R_1 xx l_2/l_1`

= `4.80 xx 640/80`

= 4.80 × 8

= 38.4 Ω

Thus, the resistance of the conductor of length 640 cm is 38.4 Ω.

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Chapter 7: Electric Circuits, Resistance and Ohm's Law - EXERCISE-1 [Page 149]

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Goyal Brothers Prakashan A New Approach to ICSE Physics [English] Class 10
Chapter 7 Electric Circuits, Resistance and Ohm's Law
EXERCISE-1 | Q 10. (c) | Page 149
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