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Question
A concave mirror produces a two times magnified virtual image of an object kept 10 cm in front of it. Calculate the focal length of the mirror.
Numerical
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Solution
Given: The object is kept 10 cm in front of the mirror, so u = −10 cm
A virtual image in a concave mirror is always erect, so the magnification is positive. Two-fold magnification, m = +2
Using the magnification formula for mirrors:
m = `-v/u`
2 = `-v/-10`
2 = `v/10`
v = 2 × 10
v = 20
The positive sign indicates the virtual image is formed 20 cm behind the mirror.
By using the mirror formula:
`1/f = 1/v + 1/u`
= `1/20 + 1/-10`
= `1/20 - 1/10`
= `1/20 - 2/20`
= `(1 - 2)/20`
`1/f = -1/20`
f = −20 cm
The focal length of the concave mirror is −20 cm. The negative sign confirms the mirror is concave.
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