Question

A coin is tossed 800 times and the outcomes were noted as: Head:415 ,Tail:385 

Find the probabiity of the min showing up (i)a head ,(ii) a tai .

Answer 1

As the coin is tossed 800 times , the total number of trials is 800. Let E₁ and E₂ be the events of the coin coming up with a head and a tail respectively . 

The number of times E₁ occurs = 415 and the number of times E₂ occurs = 385

`therefore "P"("E"_1) = 415/800 = 83/160` , and

`"P"("E"_2) = 385/800 = 77/160`