Advertisements
Advertisements
Question
A coin is tossed twice. Find the probability of getting: exactly one tail
Sum
Advertisements
Solution
Exactly one tail
Possible number of favourable outcomes = 2 (i.e. TH and HT)
Total number of possible outcomes = 4
∴ P(E) = `"Number of favourable outcomes"/"Total number of possible outcomes"`
= `2/4 = 1/2`
shaalaa.com
Is there an error in this question or solution?
