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Question
A coil of 100 turns, each of area 0.02m2 is kept in a uniform field of induction 3.5 x10-5 T. If the coil rotates with a speed of 6000 r.p.m. about an axis in the plane of the coil and perpendicular to the magnetic induction, calculate peak value of e.m.f. induced in the coil.
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Solution
Given: f = 6000 r.p.m = 100 Hz, N = 100, A = 0.02 m2, B = 3.5 10-5 T
To find: peak e.m.f (e0)
Formula: e0 = 2πfBNA
Calculation: From formula,
e0 = 2 x 3.14 x 100 x 100 x 0.02 x 3.5 x 10-5
∴ e0 = 43.99 x 10-3 V
The peak value of e.m.f. induced in the coil is 43.99 x 10-3 V.
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