Question

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:

Major sector [Use π = 3.14]

Answer 1

Area of sector = `theta/(360°) xxpir^2`

`= (90°)/(360°) xx 314 /100 xx 10 xx 10`cm²

= `1/4 xx 314 ` cm²

`= 157/2` cm²

= 78.5 cm²

Area of the major sector = [Area of the circle] - [Area of the sector]

= `pir^2 - 78.5  "cm"^2`

`= [314/100 xx 10xx10 - 78.5]`cm²

= [314 − 78.5]cm²

= 235.5 cm²