Advertisements
Advertisements
Question
A chord is at a distance of 15 cm from the centre of the circle of radius 25 cm. The length of the chord is
Options
25 cm
20 cm
40 cm
18 cm
Advertisements
Solution
40 cm
Explanation;
Hint:
In the right triangle OAC,
AC2 = OA2 – OC2
= 252 – 152
= (25 + 15)(25 – 15)
= 40 × 10
AC2 = 400
AC = `sqrt(400)`
= 20
Length of the chord AB = 20 + 20 = 40 cm.
APPEARS IN
RELATED QUESTIONS
In the given figure, PQ is chord of a circle with centre O an PT is a tangent. If
∠QPT = 60°, find the ∠PRQ.

In Fig. 8.78, there are two concentric circles with centre O. PRT and PQS are tangents to the inner circle from a point P lying on the outer circle. If PR = 5 cm, find the length of PS.

ABC is a right triangle in which ∠B = 90°. If AB = 8 cm and BC = 6 cm, find the diameter of the circle inscribed in the triangle.
Two concentric circles with center O have A, B, C, D as the points of intersection with the lines L shown in the figure. If AD = 12 cm and BC s = 8 cm, find the lengths of AB, CD, AC and BD.
Use the figure given below to fill in the blank:
R is the _______ of the circle.

A, B, C are any points on the circle with centre O. If m(arc BC) = 110° and m(arc AB) = 125°, find measure arc AC.
On a common hypotenuse AB, two right triangles ACB and ADB are situated on opposite sides. Prove that ∠BAC = ∠BDC.
The circumcentre of the triangle ABC is O. Prove that ∠OBC + ∠BAC = 90º.
From the figure, identify a segment.

The circumcentre of a triangle is the point which is ______.
