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Question
A charged particle 'q' is shot towards another charged particle 'Q' which is fixed, with a speed 'v'. It approaches 'Q' upto a closest distance r and then returns. If q were given a speed of '2v' the closest distances of approach would be ______.
Options
r/2
2 r
r
r/4
MCQ
Fill in the Blanks
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Solution
A charged particle 'q' is shot towards another charged particle 'Q' which is fixed, with a speed 'v'. It approaches 'Q' upto a closest distance r and then returns. If q were given a speed of '2v' the closest distances of approach would be r/4.
Explanation:
`1/2 "mv"^2 = "kQq"/"r"`
⇒ `1/2"m"(2"v")^2 = "kqQ"/"r"`
⇒ r' = `"r"/4`
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Work Done in Carrying a Charge
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