Question

A charged particle 'q' is shot towards another charged particle 'Q' which is fixed, with a speed 'v'. It approaches 'Q' upto a closest distance r and then returns. If q were given a speed of '2v' the closest distances of approach would be ______.

पर्याय

• r/2

• 2 r

• r

• r/4

Answer 1

A charged particle 'q' is shot towards another charged particle 'Q' which is fixed, with a speed 'v'. It approaches 'Q' upto a closest distance r and then returns. If q were given a speed of '2v' the closest distances of approach would be r/4.

Explanation:

`1/2 "mv"^2 = "kQq"/"r"`

⇒ `1/2"m"(2"v")^2 = "kqQ"/"r"`

⇒ r' = `"r"/4`