Question

A camping tent in hemispherical shape of radius 1.4 m, has a door opening of area 0.50 m². Outer surface area of the tent is ______.

Options

• 11.78 m²

• 12.32 m²

• 11.82 m²

• 12.86 m²

Answer 1

A camping tent in hemispherical shape of radius 1.4 m, has a door opening of area 0.50 m². Outer surface area of the tent is 11.82 m².

Explanation:

Given:

Radius r = 1.4 m

Area of door = 0.50 m²

Using `π = 22/7`:

Net outer surface area = CSA of hemisphere – Area of door

CSA of hemisphere = 2πr²

= `2 xx 22/7 xx (1.4) xx (1.4)`

= 44 × 0.2 × 1.4

= 8.8 × 1.4

= 12.32 m²

Now, Net surface area:

Area = 12.32 – 0.50

= 11.82 m²

The outer surface area of the tent is 11.82 m².