Question

A boy stands 83 m in front of a high wall and then blows a whistle. Calculate the time interval when hears an echo. Speed of sound is 332 ms⁻¹.

Answer 1

Distance between wall and boy (d) = 83 m

Speed of sound (v) = 332 ms⁻¹

\[ \text{Time } (\mathrm{t}) = \frac{2d}{v}\]

\[= \frac{2 \times 83}{332} \]

= 0.5 s