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Question
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears a two-digit number.
Sum
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Solution
We have total number of discs = 90
Total number of possible outcomes = 90
Since the two-digit numbers are 10, 11, 12, ....., 90.
∴ Number of two-digit numbers: 90 − 9 = 81
∴ Number of favourable outcomes = 81
∴ P (getting a two-digit number) = `"Number of favourable outcomes"/"Total number of possible outcomes"`
= `81/90`
= `9/10`
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