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Question
A box contains 75 tickets numbered 1 to 75. A ticket is drawn at random from the box. What is the probability that, number on ticket is divisible by 6?
Sum
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Solution
The box contains 75 tickets numbered 1 to 75.
∴ 1 ticket can be drawn from the box in 75C1 = 75 ways.
∴ n(S) = 75C1 = 75.
Let A be the event that number on ticket is divisible by 6.
∴ A = {6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72}
∴ n(A) = 12
∴ P(A) = `("n"("A"))/("n"("S")`
= `12/75`
= `4/25`
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