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Question
A box contains 75 tickets numbered 1 to 75. A ticket is drawn at random from the box. What is the probability that, number on ticket is divisible by 3 and 5?
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Solution
The box contains 75 tickets numbered 1 to 75.
∴ 1 ticket can be drawn from the box in 75C1 = 75 ways.
∴ n(S) = 75
Let D be the event that number on ticket is divisible by 3 and 5 i.e., divisible by L.C.M. of 3 and 5 i.e., 15
D = {15, 30, 45, 60, 75}
∴ n(D) = 5
∴ P(D) = `("n"("D"))/("n"("S")`
= `5/75`
= `1/15`
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