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A Box Contains 3 Yellow, 4 Green, and 8 Blue Tickets. a Ticket is Chosen at Random. Find the Probability that the Ticket Is: (I) Yellow (Ii) Green (Iii) Blue (Iv) Red (V) Not Yellow - Mathematics

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Question

A box contains 3 yellow, 4 green, and 8 blue tickets. A ticket is chosen at random. Find the probability that the ticket is:
(i) yellow
(ii) green
(iii) blue
(iv) red
(v) not yellow

Sum
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Solution

Number of yellow tickets = 3

Number of green tickets = 4

Number of blue tickets = 3 + 4 + 8 = 15

(i) P (getting a yellow ticket) =`3/15=1/5`

(ii) P (getting a green ticket) =`4/15`

(iii) P (getting a blue ticket) =`8/15`

(iv) Since, Basket contains yellow, green and blue tickets only.

∴ Number or red tickets = 0

∴ P (getting an red ticket) =`0/15=0`

(v) Total number of green and blue tickets = 4 + 8 = 12 tickets

P (not getting yellow ticket) = P(getting either green or blue ticket) =`12/15=4/5` 

OR

P (not getting a yellow ticket) =`1-1/5=(5-1)/5=4/5`

shaalaa.com
Concept for Feel of Probability Using Data Through Experiments.
  Is there an error in this question or solution?
Chapter 22: Probability - Exercise 22 (B)

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Selina Concise Mathematics [English] Class 7 ICSE
Chapter 22 Probability
Exercise 22 (B) | Q 6

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