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Question
A Ticket is randomly selected from a basket containing 3 green, 4 yellow, and 5 blue tickets. Determine the probability of getting:
(i) a green ticket
(ii) a green or yellow ticket.
(iii) an orange ticket.
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Solution
Number of green tickets = 3
Number of yellow tickets = 4
Number of blue tickets = 5
Total Number of tickets = 3 + 4 + 5 = 12
(i) P (getting a green tickets) =`3/12=1/4`
(ii) Total Number of green and yellow tickets = 3 + 4 = 7 tickets
P (getting a green or yellow ticket) = `7/12`
(iii) Since, Basket contains green, yellow and blue tickets only.
∴ Number or orange tickets = 0
∴ P (getting an orange ticket) = `0/12=0`
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