Advertisements
Advertisements
Question
A box contains 100 red cards, 200 yellow cards and 50 blue cards. If a card is drawn at random from the box, then find the probability that it will be (i) a blue card (ii) not a yellow card (iii) neither yellow nor a blue card.
Advertisements
Solution
Number of red cards = 100
Number of yellow cards = 200
Number of blue cards = 50
Total number of cards = 100 + 200 + 50 = 350
(i)
`P(\text{a blue card})=(\text{Number of blue card})/(\text{Total number of card})`
`=50/350`
`=1/7`
(iii)
`P(\text{Neither yellow nor a blue card})=(\text{Number of cards which are neither yellow nor blue})/(\text{Total number of cards})`
`=(\text{Number of red cards})/(\text{Total number of cards})`
`=100/350`
`=2/7`
shaalaa.com
Is there an error in this question or solution?
