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Question
A bag contains six identical black balls. A child withdraws one ball from the bag without looking into it. What is the probability that he takes out a black ball?
Sum
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Solution
Possible number of outcomes = 6 = number of balls in the bag
n(S) = 6
E = event of drawing a black ball = number of black balls in the bag = 6
n(E) = 6
Probability of drawing a black ball = P(S)
= `(n(E))/(n(S))`
= `6/6`
= 1
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