Question

A bag contains cards which are numbered from 2 to 90. A card is drawn at random from the bag. Find the probability that it bears a two digit number

Answer 1

Total no. of possible outcomes = 89 {2, 3, 4, …., 90}

 Let E ⟶ event of getting a 2 digit no.

No. favourable outcomes = 81 {10, 11, 12, 13, ….., 80}

P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`= 81/89