Question

A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is

Options

• \[\frac{1}{5}\]

• \[\frac{3}{25}\]

• \[\frac{4}{25}\]

• \[\frac{2}{25}\]

Answer 1

The total number of cards in the bag is 25.
∴ Total number of outcomes = 25
The numbers from 1 to 25 which are divisible by both 2 and 3 are 6, 12, 18 and 24.
So, the favourable number of outcomes are 4.
∴ P(number on the drawn card is divisible by both 2 and 3) = \[\frac{\text{ Favourable number of outcomes }}{\text{ Total number of outcomes }} = \frac{4}{25}\]