Question

A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is neither white nor black.

Answer 1

Total no. of possible outcomes = 8 + 6 + 4 = 18 {8 red, 6 white, 4 black}

E ⟶ event of getting neither white nor black.

No. of favourable outcomes = 15 – 6 – 4 = 8 {Total balls – no. of white balls – no. of black balls}

Probability, P(E) = `"No. of favorable outcomes"/"Total no. of possible outcomes"`

P(E) = `8/18`

= `4/9`