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Question
A bag contains 5 white, 7 red and 4 black balls. If four balls are drawn one by one with replacement, what is the probability that none is white?
Sum
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Solution
Total number of balls = 5 + 7 + 4 = 16
Total number of non-white balls = 7 + 4 = 11
∴ Probability of drawing a non-white ball = `11/16`
Since, balls are drawn one by one with replacement.
So, the probability of drawing non-white balls 4 times
= `(11/16)^4`
= `14641/65536`
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