Question

A and B are two events such that, P(A) = 0.42, P(B) = 0.48, and P(A ∩ B) = 0.16. Find P(not B)

Answer 1

P(A) = 0.42 

P(B) = 0.48

P(A ∩ B) = 0.16

P(not B) = `"P"(bar"B")` = 1 – P(B)

= 1 – 0.48

= 0.52