Advertisements
Advertisements
Question
A and B are together 90 years old. Five years ago A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years respectively.
Options
True
False
Advertisements
Solution
This statement is True.
Explanation:
Let the age of A be x years.
Then, age of B = (90 – x) years
Five years ago, the age of A = (x – 5) years
The age of B = 90 – x – 5 = (85 – x) years
Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years, respectively.
APPEARS IN
RELATED QUESTIONS
A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers?
Sum of the digits of a two digit number is 9. When we interchange the digits it is found that the resulting new number is greater than the original number by 27. What is the two-digit number?
Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him Rs 50 per metre and trouser material that costs him Rs 90 per metre. For every 2 meters of the trouser material he buys 3 metres of the shirt material. He sells the materials at 12% and 10% profit respectively. His total sale is Rs 36660. How much trouser material did he buy?
A grandfather is ten times older than his granddaughter. He is also 54 years older than her. Find their present ages
Aman’s age is three times his son’s age. Ten years ago he was five times his son’s age. Find their present ages.
Arjun is twice as old as Shriya. Five years ago his age was three times Shriya’s age. Find their present ages.
The digit in the tens place of a two-digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is ______.
Sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. Find the number.
After 12 years, Kanwar shall be 3 times as old as he was 4 years ago. Find his present age.
