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Question
A 60 µF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit.
Numerical
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Solution

Capacitance of capacitor, C = 60 μF = 60 × 10−6 F
Supply voltage, V = 110 V
Frequency, f = 60 Hz
Angular frequency, ω = 2πr
Capacitive reactance Xc = `1/(ω"C")`
= `1/(2pi "fC")`
= `1/(2 xx 3.14 xx 60 xx 60 xx 10^-6)`
= 44.2 Ω
The rms value of current is given as:
`"I" = "V"/"X"_"c"`
= `110/44.2`
= 2.49 A
Hence, the rms value of the current is 2.49 A.
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