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Karnataka Board PUCPUC Science 2nd PUC Class 12

A 60 µF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit. - Physics

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Question

A 60 µF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit.

Numerical
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Solution

Capacitance of capacitor, C = 60 μF = 60 × 10−6 F

Supply voltage, V = 110 V

Frequency, f = 60 Hz

Angular frequency, ω = 2πr

Capacitive reactance Xc = `1/(ω"C")`

= `1/(2pi "fC")`

= `1/(2 xx 3.14 xx 60 xx 60 xx 10^-6)`

= 44.2 Ω

The rms value of current is given as:

`"I" = "V"/"X"_"c"`

= `110/44.2`

= 2.49 A

Hence, the rms value of the current is 2.49 A.

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Chapter 7: Alternating Current - EXERCISES [Page 200]

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NCERT Physics [English] Class 12
Chapter 7 Alternating Current
EXERCISES | Q 7.4 | Page 200
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