Question

A 2 mH inductor is connected to 220 V, 50 Hz AC (X₁​) and then to DC (X₂). Find X_1​ and X₂.

Options

• 6.28 Ω, zero

• 6.28 Ω, infinity

• 0.628 Ω, zero

• 0.628 Ω, infinity

Answer 1

0.628 Ω, zero

Explanation:

For AC circuits, X_L = ωL

X_L = 2πfL

XL = 2π × 50 × 2 × 10^-3

Hence, X₁ = 0.628 Ω

For DC circuits, ω = 0

X_L = ωL = 0

X₂ = 0