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Question
A 12 V, 60 W lamp is connected to 220 V AC via an ideal transformer. Find the primary current.
Options
2.7 A
3.7 A
0.37 A
0.27 A
MCQ
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Solution
0.27 A
Explanation:
As transformer is ideal.
So, Poutput = Pinput = 60
Ip Vp = 60
Ip = \[\frac {60}{V_p}\] = \[\frac {60}{220}\] = \[\frac {3}{11}\] = 0.27 A
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