Question

A 10-V battery can deliver 2 × 10⁻³ C of charge through a 20 resistance. What will be the amount of work done in 10 s?

Answer 1

Given Data:

Potential difference of the battery (V) = 10 V

Electric charge (Q) = 2 × 10⁻³ C

Resistance (R) = 20 Ω

Time interval (t) = 10 s

Formula:

W = V × Q

= 10 × (2 × 10⁻³)

= 2 × 10¹ × 10⁻³

= 2 × 10¹⁻³

= 2 × 10⁻² J

The amount of work done is 2 × 10⁻² Joules.