Question

\({ }_{92} \mathrm{U}^{236} \longrightarrow{ }_{56} \mathrm{Ba}^{\mathrm{x}}+{ }_{y}\mathrm{~K} r^{92}+3{ }_{0} \mathrm{n}^{1} + \text{energy}\)

In the above nuclear equation, the values of x and y are:

Options

• x = 141, y = 34

• x = 139, y = 35

• x = 141, y = 36

• x = 142, y = 37

Answer 1

x = 141, y = 36

Explanation:

In any nuclear equation, the total mass number and total atomic number must balance.

Mass number: 236 = x + 92 + 3, so x = 141

Atomic number: 92 = 56 + y + 0, so y = 36