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Question
5 × 2 a multiple of 11?
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Solution
Sum of a digit in even place = x
and sum of the digits in odd place = 5 + 2 = 7
Difference of the sum of the digits in even places and in odd places = x – 7
5×2 is a multiple of 11
⇒ x – 7 = 0, 11, 22,
⇒ x = 7, 18, 29,
Since, x is a digit
x = 7
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