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Question
400 joules of work is done in bringing a charge of 2 coulombs from infinity to a given point, what is the potential at that point?
Numerical
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Solution
Given:
Work done (W) = 400 J
Electric charge (Q) = 2 C
Formula:
\[V = \frac{W}{Q}\]
\[= \frac{400}{2}\]
= 200 V
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Chapter 7: Electric Circuits, Resistance and Ohm's Law - EXERCISE-1 [Page 149]
