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30 circular plates, each of radius 14 cm and thickness 3 cm are placed one above the another to form a cylindrical solid. Find the total surface area. - Mathematics

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Question

30 circular plates, each of radius 14 cm and thickness 3 cm are placed one above the another to form a cylindrical solid. Find the total surface area.

Sum
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Solution

Given, radius of a circular plate, r = 14 cm

Thickness of a circular plate = 3 cm

Thickness of 30 circular plates = 30 × 3 = 90 cm

Since, 30 circular plates are placed one above the another to form a cylindrical solid.

Then, Height of the cylindrical solid, h = Thickness of 30 circular plates = 90 cm

Total surface area of the cylindrical solid so formed

= `2πr(h + r) = 2 xx (22/7) xx 14(90 + 14)`

= 44 × 2 × 104

= 9152 cm2

Hence, the total surface area of the cylindrical solid is 9152 cm2.

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Chapter 13: Surface Area & Volumes - Exercise 13.4 [Page 128]

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NCERT Exemplar Mathematics [English] Class 9
Chapter 13 Surface Area & Volumes
Exercise 13.4 | Q 8. (i) | Page 128
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